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Q) Find the domain of 𝑝(𝑥)=sin^(−1) (1−2𝑥^2 ). Hence,find the value of 𝑥 for which p(𝑥)=𝜋/6.
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If 𝑦=𝑠𝑖𝑛^(−1) 𝑥,−1≤𝑥≤0,then the range of 𝑦 is(A) ((−𝜋)/2,0)(B) [(−𝜋)/2,0](C) [(−𝜋)/2,0
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